Anonymous 11/28/2023 06:20:00 No. 26420 [Open] [Reply] Actions report Translate Thread... Hide Thread Translate... Hide Post A={0:(1/4), 1:(1/2), 2:(1/4)} B={0:(1/8), 1:(3/8), 2:(3/8), 3:(1/8)} B побеждает если: А.0*(B.1+B.2+B.3) + (A.1+A.0)*(B.2+B.3) + B.3 = 1/4*7/8+ 3/4*4/8 + 1/8 = (7+12+4)/32 = 23/32 A побеждает если B не побеждает: 1-(23/32) = 9/32